Example Of ICE BOX No X Just Problem No Work
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Changed: 3c3
1 H
2 (g)
+ 1 I
2 (g)
<=> 2 HI
(g)
1 H
2 (g)
+ 1 I
2 (g)
⇔ 2 HI
(g)
Changed: 5c5,21
⇔
Initially I have 3.00 moles H
2
and 4.00 moles I
2
in a 1.0 L container. To reach equilibrium, 2.00 moles H
2
react. Calculate the equilibrium position and K using the following reversible reaction.
1 H
2 (g)
+ 1 I
2 (g)
⇔ 2 HI
(g)
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Last edited November 7, 2019 12:04 pm
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