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Here are the answers to 2021-2022 Honors Chem328 Polarity, IMF and Physical Properties Review HW
1)
2)
- N1H3: 8ve-, 3 single bonds, N is central atom with 1 lone pair (LP), Pyramidal (107.0°), sp3
- B1F3: 24ve-, 3 single bonds, B is central atom with no LP, Trigonal planar, 120°, sp2
- N2: 10ve-, 1 triple bond, no central atom, Linear (180°), NA
- C1O2: 16ve-, 2 double bond, C is central atom with 0 LP, Linear (180°), sp
3)
- CCl4, ΔEN =0.5, 4 non-polar bonds, Tetrahedral (sym), NA, non-polar molecule, LDF
- BeCl2, ΔEN =1.5, 2 polar bonds, Linear (sym), Yes, non-polar molecule, LDF
- CS2, ΔEN=0.0, 2 non-polar bonds, Linear (sym), non-polar molecule, LDF
- NF3, ΔEN=1.0, 3 polar bonds, Pyramidal (not sym), polar molecule, dipole-dipole
4) sp3 hybridized
5)
6)+-->, Arrow over the more electronegative atom (or whatever way you memorize the symbol).
7) Ionic ΔEN> or = 1.7
polar bond is 1.7<ΔEN> or = 0.8
non-polar ΔEN<0.8
8) Assume polar prove non-polar
9) Ionic compound/bond same strength as metals/metallic bonds (Highest IMF)
Polar molecules containing H-O,H-N,H-F (IMF name is hydrogen bonding)
Polar molecules that don't (IMF name is dipole-dipole interaction)
Non-polar molecules (IMF is London Dispersion Forces, LDF) (Lowest IMF).
10) Dipole-dipole (D - D) interaction
11) Yes
12) No, polar or non-polar is for covalent (sharing) bonds
13) False
14) NH3, has more Hydrogen bond (actually it is H2O1)
15) Boiling is based on CF, London dispersion forces (LDF). Octane has a higher IMF since it a higher molar meaning more electrons so more Instantaneous dipoles. So since IMF is higher, it will take more energy (higher boiling point) so boiling first means lower boiling point (Hexane).
16) H2O1 is a polar molecule and oil is a hydrocarbon (CxHy) a non-polar molecule. So H2O1 exerts coloumbic force (CF) while oil does not. So H2O1 molecules are interacting with other H2O1 molecule so they will "push oil molecules" around so they will be together.