Editing revision 12 of Answers To 2021-2022 Honors Chem328 Polarity, IMF And Physical Properties Review HW
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Here are the answers to [[2021-2022 Honors Chem328 Polarity, IMF and Physical Properties Review HW]]<br> <br> 1a) Ionic <br> 1b) Polar <br> 1c) Non-polar <br> 1d) Polar <br> 1e) Ionic <br> 1f) Polar <br> <br> 2)<br> *P<sub>1</sub>Cl<sub>5</sub>: 40ve<sup>-</sup>, P is central atom & 0LP, Trigonal bipyramidal (90,120), dsp<sub>3</sub> hybridized *B<sub>1</sub>F<sub>3</sub>: 24ve<sup>-</sup>, 3 single bonds, B is central atom with no LP, Trigonal planar, 120°, sp<sup>2</sup> *N<sub>2</sub>: 10ve<sup>-</sup>, 1 triple bond, no central atom, Linear (180°), NA *S<sub>1</sub>O<sub>2</sub>: 18ve<sup>-</sup>, 1 single, 1 double bond, S is central atom with 1 LP, Planar unknown bond angle (can't be more specific), sp<sup>2</sup><br> <br> 3)<br> *CCl<sub>4</sub>, ΔEN =0.5, 4 non-polar bonds, Tetrahedral (sym), NA, non-polar molecule, LDF<br> *<nowiki>BeCl</nowiki><sub>2</sub>, ΔEN =1.5, 2 polar bonds, Linear (sym), Yes, non-polar molecule, LDF *CS<sub>2</sub>, ΔEN=0.0, 2 non-polar bonds, Linear (sym), non-polar molecule, LDF *NF<sub>3</sub>, ΔEN=1.0, 3 polar bonds, Pyramidal (not sym), polar molecule, dipole-dipole<br> <br> 4) dsp<sub>3</sub> hybridized<br> <br> 5)No the compound can not exist because N has only s & p orbitals and you d orbitals to make the hybridization (dsp<sub>3</sub>). <br> <br> 6)+-->, Arrow over the more electronegative atom (or whatever way you memorize the symbol).<br> <br> 7) Ionic ΔEN> or = 1.7<br> polar bond is 1.7<ΔEN> or = 0.8<br> non-polar ΔEN<0.8<br> <br> 8) Assume polar prove non-polar<br> <br> 9) Ionic compound/bond same strength as metals/metallic bonds (Highest IMF)<br> Polar molecules containing H-O,H-N,H-F (IMF name is hydrogen bonding)<br> Polar molecules that don't (IMF name is dipole-dipole interaction)<br> Non-polar molecules (IMF is London Dispersion Forces, LDF) (Lowest IMF).<br> <br> <br> 10) Dipole-dipole (D - D) interaction<br> <br> 11) Yes<br> <br> 12) No, polar or non-polar is for covalent (sharing) bonds<br> <br> 13) False<br> <bR> 14) NH<sub>3</sub>, has more Hydrogen bond (actually it is H<sub>2</sub>O<sub>1</sub>)<br> <br> 15) Boiling is based on CF, London dispersion forces (LDF). Octane has a higher IMF since it a higher molar meaning more electrons so more Instantaneous dipoles. So since IMF is higher, it will take more energy (higher boiling point) so boiling first means lower boiling point (Hexane). <br> <br> 16) H<sub>2</sub>O<sub>1</sub> is a polar molecule and oil is a hydrocarbon (C<sub>x</sub>H<sub>y</sub>) a non-polar molecule. So H<sub>2</sub>O<sub>1</sub> exerts coloumbic force (CF) while oil does not. So H<sub>2</sub>O<sub>1</sub> molecules are interacting with other H<sub>2</sub>O<sub>1</sub> molecule so they will "push oil molecules" around so they will be together.<br> <br>
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