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<center>'''Empirical Formula'''</center><br> <br> ''The empirical formula of a substance represents the smallest whole number ratio of the elements in that substance''<br> *''ionic compounds''-only have an empirical formula<br> *''molecular compounds''-have both an empirical and a molecular formula<br> '''Steps to finding the empirical formula of a substance:'''<br> #Find the mass percent of a certain element in the original compound.<br> #Assume 100g of the compound and find the number of moles present of each element using their atomic masses.<br> #Divide each mole value by the smallest of the values.<br> ##If, after rounding, you get a whole number result, then these values will represent the subscripts of the elements in the compound in its empirical form.<br> ##If you do not end up with whole numbers as a result of the division, multipy all of the results by an integer until all of the subscripts turn out to be whole numbers.<br> <br> '''Example:'''<br> '''''Suppose .1234g of a substance, that is composed only of the elements Carbon, Hydrogen, and Oxygen, is reacted with oxygen to form .1345g CO<sub>2</sub> and .1456g H<sub>2</sub>O. Asume that all of the Carbon is consumed to form CO<sub>2</sub> and that all of the Hydrogen is consumed to form H<sub>2</sub>O. Find the empirical formula of the substance.'''''<br> <br> #'''To find the mass percent of Carbon in the original compound:'''<br> **'''First you must determine the molar mass of CO<sub>2</sub>:'''<br> <center>C: 1mol x 12.01g/mol = 12.01g</center><br> <br> <center>O: 2mol x 16.00g/mol = 32.00g</center><br> <br> <center> Molar Mass of CO<sub>2</sub>=44.01g/mol</center><br> <br> **'''Next, find the mass percent of carbon in CO<sub>2</sub><br>'''
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