Editing Double Replacement - Solid Formed
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The direction to determine if a double replacement reaction occurs via formation of a solid is as follows:<br> <br> <b>Remember: In double replacement reaction, you simply switch one set of ions so that each ion is combining with a new ion (switch dance partners) to form the potential products</b><br> <br> <i>Click here for Solubility table, [[Solubility Table]].</i><br> 1. With the correct chemical formula of the potential products, look for the anion in the first potential product. Determine its chemical name and then look on the [[Solubility Table]] for the appropriate <b>row</b> where the anion name matches the name from the first column of the row.<br> <br> 2. Determine the correct chemical name of the cation. Most anions will have two rows, each with a separate set of cations or the words, <i>all other (second column)</i>.<br> <br> 3. Once you determine the correct row (from the second column), go to the third column. There will be two words, soluble or low solubility. Soluble = aqueous and Low solubility = solid.<br> <br> 4. Now you know the phase of that potential product. Repeat for the other potential product.<br> <br> 5. As stated above, if one of these potential products are <b>solid</b>, then the <b>reaction occurs</b>. If <b>neither</b> potential products is a <b>solid</b>, the <b>reaction will not occur</b>.<br> <b>Example</b><br> Ca<sub>1</sub>Cl<sub>2 (aq)</sub> + Na<sub>2</sub>(<nowiki>SO</nowiki><sub>4</sub>)<sub>1 (aq) </sub> --><br> <br> <i>First potential product:</i> Ca<sup>2+</sup> and <nowiki>SO</nowiki><sub>4</sub><sup>2-</sup>.<br> <b>Step 1</b>: <nowiki>SO</nowiki><sub>4</sub><sup>2-</sup> is sulfate, so find on [[Solubility Table]] in 1st Column.<br> <b>Step 2</b>: Then go to row that has Ca<sup>2+</sup>, cation, in the 2nd Column. <br> <b>Step 3</b>: Then go to the 3rd Column and you see it says <b>Low Solubility</b>. This means it <b>forms a solid</b>.<br> <b>Step 4</b>: Since it forms a solid product, the reaction occurs and this product is Ca<sub>1</sub>(<nowiki>SO</nowiki><sub>4</sub>)<sub>1 (s)</sub><br> <br> <i>2nd potential product: </i>Na<sup>1+</sup> and Cl<sup>1-</sup>.<br> <b>Step 1</b>: Cl<sup>1-</sup> is chloride, so find on [[Solubility Table]] in 1st Column.<br> <b>Step 2</b>: Then go to row that has Na<sup>1+</sup>, cation, in the 2nd Column. Here, there is no column that says it but it is one of the <i>all others</i>.<br> <b>Step 3</b>: Then go to the 3rd Column and you see it says <b>Soluble</b>. This means it is <b>aqueous</b>.<br> <b>Step 4</b>: This product is Na<sub>1</sub>Cl<sub>1 (aq)</sub><br> <br> <b>Step 5:</b> So the overall reaction that does occur (since one of products is a solid) is:<br> <br> Ca<sub>1</sub>Cl<sub>2 (aq)</sub> + Na<sub>2</sub>(<nowiki>SO</nowiki><sub>4</sub>)<sub>1 (aq) </sub> --> Ca<sub>1</sub>(<nowiki>SO</nowiki><sub>4</sub>)<sub>1 (s)</sub> + Na<sub>1</sub>Cl<sub>1 (aq)</sub><br> <br> You then have to balance it, which is another story.<br>
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