Answers For Molecular Geometry And Hybridization For More Exceeding Octet Rule And Resonance Species Homework

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Difference (from prior major revision) (no other diffs)

Removed: 8,12d7

2) CN^1- : Total #ve: 10ve, no central atom, 1 triple bond, linear, 180°

3) P₁O₄^3- : Total #ve: 32ve, P is central atom and 0LP, 4 single bonds, tetrahedral, 109.5°, sp³ hybridized

4) NO₂^1- : Total #ve: 18ve, N is central atom and 1 LP, 1 double bond, 1 single bond, planar, unknown bond angle, sp² hybridized.

Added: 13a9

3) CO₃^2- : Total #ve: 24ve, C is central atom and 0 LP, 1 double bond, 2 single bond, Trigonal planar, 120°, sp² hybridized.

Added: 14a11

Changed: 17c14

Here are the answers to Exceeding Octet Rule and Resonance Species Homework handout including Molecular Geometry and Hybridization.

1) NO₃^1- : Total #ve: 24ve, N is central atom and 0 LP, 1 double bond, 2 single bond, Trigonal planar, 120°, sp² hybridized.

2) As₁F₅ Total # ve: 40ve, As is central atom no LP, 5 single bonds, Trigonal bipyramidal, 90°, 120°, dsp³ hybridized

3) CO₃^2- : Total #ve: 24ve, C is central atom and 0 LP, 1 double bond, 2 single bond, Trigonal planar, 120°, sp² hybridized.

4) Se₁Br₆ Total # ve: 48ve, Se is central atom no LP, 6 single bonds, Octahedral, 90°, 90°, d²sp³ hybridized