Molecular Geometry And Hybridization Answer To More Lewis Dot Structure Homework

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Difference (from prior major revision) (no other diffs)

Changed: 3c3

1) P₁I₅ Total # ve: 40ve, P is central atom no LP, 5 single bonds, Trigonal bipyramidal, 90, 120

1) P₁I₅ Total # ve: 40ve, P is central atom no LP, 5 single bonds, Trigonal bipyramidal, 90°, 120°, dsp³ hybridized

Changed: 5c5

2) CN^1- : Total #ve: 10ve, no central atom, 1 triple bond, linear, 180

2) CN^1- : Total #ve: 10ve, no central atom, 1 triple bond, linear, 180°

Changed: 7c7,9

3) P₁O₄^3- : Total #ve:

3) P₁O₄^3- : Total #ve: 32ve, P is central atom and 0LP, 4 single bonds, tetrahedral, 109.5°, sp³ hybridized

4) NO₂^1- : Total #ve: 18ve, N is central atom and 1 LP, 1 double bond, 1 single bond, planar, unknown bond angle, sp² hybridized.

Here are the answers to More Lewis Dot Structure Homework handout including Molecular Geometry and Hybridization.

1) P₁I₅ Total # ve: 40ve, P is central atom no LP, 5 single bonds, Trigonal bipyramidal, 90°, 120°, dsp³ hybridized

2) CN^1- : Total #ve: 10ve, no central atom, 1 triple bond, linear, 180°

3) P₁O₄^3- : Total #ve: 32ve, P is central atom and 0LP, 4 single bonds, tetrahedral, 109.5°, sp³ hybridized

4) NO₂^1- : Total #ve: 18ve, N is central atom and 1 LP, 1 double bond, 1 single bond, planar, unknown bond angle, sp² hybridized.