4.)The numerical values for the units in the second set of parenthesis will be the conversion factor: (13.25gK)(1mol K/13.25g K)(1mol K2S/2mol K) |
4.)The numerical values for the units in the second set of parenthesis will be the conversion factor: (13.25gK)(1mol K/39.098g K)(1mol K2S/2mol K) |
6.)Multiply through all of the parenthesis |
6.)Multiply through all of the parenthesis 7.)The answer will be the numerical value calculated with the units of the numerator in the final set of parenthesis. .1694mol K2S "Example 2:" If there is a 22.5g of Phorphorus (P) how many moles of Ca3P2 will be produced, the the reaction procedes as follows: 3Ca + 2P --> 1Ca3P2 "Answer:" .3632mol Ca3P2 |
Dimensional Analysis